JEE Main 2013PhysicsLaws of MotionMediumMCQ

JEE Main 2013 — Laws of Motion Question with Solution

JEE Main 2013 (07 Apr)

Question

A uniform cylinder of length L and mass M having cross-sectional area A is suspended, with its length vertical, from a fixed point by a massless spring, such that it is half submerged in a liquid of density σ at equilibrium position. The extension x 0 of the spring when it is in equilibrium is :
 

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Show full solutionCorrect option: A
Correct answer
A Mg k 1 - LA σ 2 M

Step-by-step explanation

kx 0 + F B = mg

kx 0 + σ L 2 Ag = Mg


x 0 = Mg - σ LAg 2 k

    = Mg k 1 - σ LA 2 M

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About this question

This is a previous-year question from JEE Main 2013, covering the Laws of Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.