JEE Main 2014PhysicsLaws of MotionMediumMCQ

JEE Main 2014 — Laws of Motion Question with Solution

JEE Main 2014 (06 Apr)

Question

A block of mass m is placed on a surface with a vertical cross section given by y=x36. If the coefficient of friction is 0.5, the maximum height above the ground at which the block can be placed without slipping is 

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Show full solutionCorrect option: A
Correct answer
A16 m

Step-by-step explanation

For block remain stationary.

μ=tanθ (θ is angle at that point)

∴tanθ=μ=12(slope)

y=x36

∴dydx=3x26=x22⇒slope=12⇒x=1

∴y=(1)36 =16 m

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About this question

This is a previous-year question from JEE Main 2014, covering the Laws of Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.