JEE Main 2017PhysicsLaws of MotionHardMCQ

JEE Main 2017 — Laws of Motion Question with Solution

JEE Main 2017 (09 Apr Online)

Question

The machine as shown has 2 rods of length 1 m connected by a pivot at the top. The end of one rod is connected to the floor by a stationary pivot and the end of the other rod has roller that rolls along the floor in a slot. As the roller goes back and forth, a 2 kg weight moves up and down. If the roller is moving towards right at a constant speed, the weight moves up with a :

Choose an option

Show full solutionCorrect option: C
Correct answer
CDecreasing speed

Step-by-step explanation



vA=dxdt=d2lcosθdt=-2lsinθdθdt and 

Vertical velocity of B, vB=dydt=dlsinθdt=lcosθdθdt

vAvB=-2tanθ⇒vB=-vAcotθ2 
 
θ→increase

cotθ→decrease

Hence, vB→decrease.

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About this question

This is a previous-year question from JEE Main 2017, covering the Laws of Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.