JEE Main 2024PhysicsMechanical Properties of FluidsMediumNumerical

JEE Main 2024 — Mechanical Properties of Fluids Question with Solution

JEE Main 2024 (30 Jan Shift 2)

Question

A big drop is formed by coalescing 1000 small identical drops of water. If E1 be the total surface energy of 1000 small drops of water and E2 be the surface energy of single big drop of water, the E1 : E2 is x: 1, where x=________.

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Show full solutionCorrect answer: 10
Correct answer
10

Step-by-step explanation

Let radius of the small drop be r and the radius of the big drop be R. Then, total volume will remain constant, therefore

1000×ρ43πr3=43πR3ρ

⇒R=10r

Initial total surface energy, E1=1000×4πr2×S and 

E2=4π(10r)2 S

⇒E1E2=101Hence, x=10.

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About this question

This is a previous-year question from JEE Main 2024, covering the Mechanical Properties of Fluids chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.