JEE Main 2014PhysicsMechanical Properties of FluidsMediumMCQ

JEE Main 2014 — Mechanical Properties of Fluids Question with Solution

JEE Main 2014 (06 Apr)

Question

An open glass tube is immersed in mercury in such a way that a length of 8 cm extends above the mercury level. The open end of the tube is then closed and sealed and the tube is raised vertically up by additional 46 cm. What will be length of the air column above mercury in the tube now ?
(Atmospheric pressure = 76 cm of Hg)

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Show full solutionCorrect option: A
Correct answer
A16 cm

Step-by-step explanation

Using isothermal process conditions



⇒ P 1 V 1 = P 2 V 2 ⇒ P 1 A ℓ 1 = P 2 A ℓ 2

8 p 0 = xp ⇒ p = 8 p 0 x     (here p0 = 76 cm of Hg)

8 p 0 x + ρ m g 54 - x = ρ m g (76)

8 x + 54 - x 76 = 1

x = 16 cm

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About this question

This is a previous-year question from JEE Main 2014, covering the Mechanical Properties of Fluids chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.