JEE Main 2025 — Mechanical Properties of Fluids Question with Solution
JEE Main 2025 (24 Jan Shift 1)
Question
The amount of work done to break a big water drop of radius ' ' into 27 small drops of equal radius is 10 J . The work done required to break the same big drop into 64 small drops of equal radius will be
Choose an option
Show full solutionCorrect option: A
Correct answer
A15 J
Step-by-step explanation
$\begin{aligned}
& W_1=s 4 \pi\left(\frac{R}{3}\right)^2 \times 27-4 \pi R^2 \cdot s \\
& \Rightarrow W_1=4 \pi R^2 \cdot s(2)=10 \text { Joule }
\end{aligned}$
Now,
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Mechanical Properties of Fluids chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2025, covering the Mechanical Properties of Fluids chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.