JEE Main 2020PhysicsMechanical Properties of FluidsEasyNumerical

JEE Main 2020 — Mechanical Properties of Fluids Question with Solution

JEE Main 2020 (03 Sep Shift 1)

Question

When a long glass capillary tube of radius 0.015cm is dipped in a liquid, the liquid rises to a height of 15 cm within it. If the contact angle between the liquid and glass to close to 0°, the surface tension of the liquid, in milliNewton m-1, is ρ(liqued) =900 kg m-3,g=10 m s-2 (Given answer in closed integer)

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Show full solutionCorrect answer: 101
Correct answer
101

Step-by-step explanation

Using the concept of rise due to surface tension,

 2Tr=hρg

T=rhρg2=15×10-5×15×10-2×900×102=101 milliNewton m-1

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About this question

This is a previous-year question from JEE Main 2020, covering the Mechanical Properties of Fluids chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.