JEE Main 2026 — Oscillations Question with Solution
JEE Main 2026 (28 January Shift 1)
Question
The displacement of a particle, executing simple harmonic motion with time period , is expressed as , where is the amplitude. The maximum value of potential energy of this oscillator is found at . The value of is .
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Show full solutionCorrect answer: 2
Correct answer
2
Step-by-step explanation
For SHM with , the potential energy is
.
Maximum potential energy occurs when , i.e., when
The first maximum occurs at , giving .
Since this is given as .
We have , so .
.
Maximum potential energy occurs when , i.e., when
The first maximum occurs at , giving .
Since this is given as .
We have , so .
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This is a previous-year question from JEE Main 2026, covering the Oscillations chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.