JEE Main 2023PhysicsThermal Properties of MatterMediumNumerical

JEE Main 2023 — Thermal Properties of Matter Question with Solution

JEE Main 2023 (29 Jan Shift 1)

Question

A body cools from 60°C to 40°C in 6 minutes. If, temperature of surroundings is 10°C. Then, after the next 6 minutes, its temperature will be ______ °C.

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Show full solutionCorrect answer: 28
Correct answer
28

Step-by-step explanation

From Newton’s law of cooling

dTdt=kTavg-T0, here, T0 is surrounding temperature.

For case 1:

60-406=k60+402-10

206=k50-10    ...1 

For case 2:

40-T6=k40+T2-10    ...2 

From equation 1, we have k=112

Putting in equation 2

40-T6=11240+T2-10

⇒10+T2=80-2T⇒2T+T2=70

⇒T=1405=28°C

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About this question

This is a previous-year question from JEE Main 2023, covering the Thermal Properties of Matter chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.