JEE Main 2019 — Thermal Properties of Matter Question with Solution
JEE Main 2019 (11 Jan Shift 2)
Question
Two rods and of identical dimensions are at temperature . If is heated upto and upto then the new lengths are the same. If the ratio of the coefficients of linear expansion of and is then the value of is
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Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
Change in length in both rods are same i.e.
$\begin{array}{l}
\frac{\alpha_{1}}{\alpha_{2}}=\frac{\Delta \theta_{2}}{\Delta \theta_{1}} \quad\left[\because \frac{\alpha_{1}}{\alpha_{2}}=\frac{4}{3}\right] \\
\frac{4}{3}=\frac{\theta-30}{180-30}
\end{array}$
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This is a previous-year question from JEE Main 2019, covering the Thermal Properties of Matter chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.