JEE Main 2023PhysicsThermal Properties of MatterMediumMCQ

JEE Main 2023 — Thermal Properties of Matter Question with Solution

JEE Main 2023 (25 Jan Shift 1)

Question

A bowl filled with very hot soup cools from 98°C to in 2 minutes when the room temperature is . How long it will take to cool from to ?

Choose an option

Show full solutionCorrect option: B
Correct answer
B1.4 minute

Step-by-step explanation

From Newton's law of cooling, we have

ΔQΔt=-KTavg-T0

Where, Q=ms∆T, m is the mass, s is the specific heat and ∆T is the temperature change.

Case 1:

∆t=2 minutes, T0=22°C

ms×122=-K98+862-22

6=-Kms70    ...1

Case 2:

ms×6Δt=-K75+692-22

6Δt=-Kms(50)   ...2

Dividing (2) by (1), we get

⇒6Δt(6)=5070

⇒Δt=75=1.4 min

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About this question

This is a previous-year question from JEE Main 2023, covering the Thermal Properties of Matter chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.