JEE Main 2023PhysicsThermal Properties of MatterEasyMCQ

JEE Main 2023 — Thermal Properties of Matter Question with Solution

JEE Main 2023 (06 Apr Shift 2)

Question

A body cools in 7 minutes from 60oC to 40oC. The temperature of the surrounding is 10oC. The temperature of the body after the next 7 minutes will be

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Show full solutionCorrect option: D
Correct answer
D28oC

Step-by-step explanation

Newton's law of cooling states that 

T1-T2t=KT1+T22-T0   ...(i)

where T0 is the temperature of the surrounding. From equation (i),

60-407×60=K60+402-10

⇒207×60=40K⇒K=207×60×40

Let the temperature of the body after the given time be x °C. By Newton's law of cooling,

40-x7×60=K40+x2-10⇒40-x7×60=114×60(20+x2)⇒160-4x=20+x⇒x=28 °C

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About this question

This is a previous-year question from JEE Main 2023, covering the Thermal Properties of Matter chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.