JEE Main 2014PhysicsThermal Properties of MatterHardMCQ

JEE Main 2014Thermal Properties of Matter Question with Solution

JEE Main 2014 (19 Apr Online)

Question

A black coloured solid sphere of radius R and mass M is inside a cavity with a vacuum inside. The walls of the cavity are maintained at temperature T0. The initial temperature of the sphere is 3T0. If the specific heat of the material of the sphere varies as αT3 per unit mass with the temperature T of the sphere, where α is a constant, then the time taken for the sphere to cool down to temperature 2T0 will be

(σ is Stefan Boltzmann constant)

Choose an option

Show full solutionCorrect option: B
Correct answer
BMα16πR2σln163

Step-by-step explanation

dθdt=-σAeMsθ4-θ04      



dθdt=-σAeMαθ3θ4-θ04

θ3θ4-θ04dθ=-σAeMαdt

Let θ4-θ04=x

4θ3dθ=dx

dx4x=-σAeMαt0t

14lnx=MσAeMαt0t

14lnθ4-θ042T03T0=-σAeMαt

14ln2T04-T043T04-T04=-σAeMαt

t=-αM4σAeln15T0480T04

=-αM4σAeln316

=-αM4σ4πR2eln316         where e=1

t=αM16πσR2ln163

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About this question

This is a previous-year question from JEE Main 2014, covering the Thermal Properties of Matter chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.