JEE Main 2019PhysicsThermal Properties of MatterMediumMCQ

JEE Main 2019 — Thermal Properties of Matter Question with Solution

JEE Main 2019 (12 Apr Shift 1)

Question

When M1 gram of ice at -10oC (specific heat =0.5 cal g-1 ℃-1 ) is added to M2 gram of water at 50 oC, finally no ice is left and the water is at 0 oC . The value of latent heat of ice, in cal g-1 is:

Choose an option

Show full solutionCorrect option: D
Correct answer
D50M2M1-5

Step-by-step explanation

Principle of calorimetry
M1Sice0--10+M1Lf=M2Swater50-0
M10.510+M1Lf=M250
5M1+M1Lf=M250
Lf=50M2M1-5

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About this question

This is a previous-year question from JEE Main 2019, covering the Thermal Properties of Matter chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.