JEE Main 2014 — Thermal Properties of Matter Question with Solution
JEE Main 2014 (12 Apr Online)
Question
Hot water cools from to in the first 10 minutes and to in the next 10 minutes. The temperature of the surroundings is:
Choose an option
Show full solutionCorrect option: B
Correct answer
B
Step-by-step explanation
By Newton's law of cooling
where is the temperature of surrounding. Now, hot water cools from to in 10 minutes,
Again, it cools from to in next 10 minutes.
Dividing equations (i) by (ii) we get
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Thermal Properties of Matter chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2014, covering the Thermal Properties of Matter chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.