JEE Main 2019 — Units and Dimensions Question with Solution
JEE Main 2019 (11 Jan Shift 2)
Question
If speed (V), acceleration (A) and force (F) are considered
as fundamental units, the dimension of Young's modulus
will be :
Choose an option
Show full solutionCorrect option: D
Correct answer
D
Step-by-step explanation
Let [Y] = [V]
Comparing power both side of similar terms we get,
solving above equations we get
so
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Units and Dimensions chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2019, covering the Units and Dimensions chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.