JEE Main 2022PhysicsUnits and DimensionsEasyMCQ

JEE Main 2022Units and Dimensions Question with Solution

JEE Main 2022 (28 Jul Shift 1)

Question

The dimensions of B2μ0 will be

(if μ0: permeability of free space and B :magnetic field)

Choose an option

Show full solutionCorrect option: C
Correct answer
CML-1T-2

Step-by-step explanation

Energy density in magnetic field is given by u=B22μ0. Therefore, dimensions of B2μ0 will be equal to the dimensions of energy per unit volume.

B2μ0=u=ML2T-2L3=ML-1T-2

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About this question

This is a previous-year question from JEE Main 2022, covering the Units and Dimensions chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.