JEE Main 2013PhysicsUnits and DimensionsMediumMCQ

JEE Main 2013 — Units and Dimensions Question with Solution

JEE Main 2013 (07 Apr)

Question

Let ∈ 0 denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then :

Choose an option

Show full solutionCorrect option: D
Correct answer
D ∈ 0 = M -1  L - 3  T 4  A 2

Step-by-step explanation

F = 1 4 π ε 0 q 1 q 2 R 2

ε 0 = q 1 q 2 4 π FR 2

Hence, ε 0 = C 2 N . m 2 = AT 2 ML T - 2 . L 2 = M -1  L - 3  T 4  A 2

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About this question

This is a previous-year question from JEE Main 2013, covering the Units and Dimensions chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.