JEE Main 2020PhysicsUnits and DimensionsEasyMCQ

JEE Main 2020 — Units and Dimensions Question with Solution

JEE Main 2020 (04 Sep Shift 1)

Question

Dimensional formula for thermal conductivity is (here K denotes the temperature):

Choose an option

Show full solutionCorrect option: D
Correct answer
DMLT–3K–1

Step-by-step explanation

k=Q/tΔxAΔT

=M1L2T−2LL2KT=M1L1T−3K−1

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About this question

This is a previous-year question from JEE Main 2020, covering the Units and Dimensions chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.