JEE Main 2022ChemistryAlcohols Phenols and EthersHardMCQ

JEE Main 2022Alcohols Phenols and Ethers Question with Solution

JEE Main 2022 (24 Jun Shift 2)

Question

Hex-4-ene-2-ol on treatment with PCC gives 'A'. 'A' on reaction with sodium hypoiodite gives 'B', which on further heating with soda lime gives 'C'. The compound 'C' is

Choose an option

Show full solutionCorrect option: C
Correct answer
C2-butene

Step-by-step explanation

Hex-4-ene-2-ol on reaction with PCC forms Hex-4-ene-2-one.

Hex-4-ene-2-one on iodoform reaction gives pent-2 enoic acid and iodoform.

Pent-2 enoic acid on decarboxylation with soda lime forms but-2-ene. 

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About this question

This is a previous-year question from JEE Main 2022, covering the Alcohols Phenols and Ethers chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.