JEE Main 2018ChemistryAlcohols Phenols and EthersHardMCQ

JEE Main 2018 — Alcohols Phenols and Ethers Question with Solution

JEE Main 2018 (08 Apr)

Question

Phenol on treatment with CO2 in the presence of NaOH followed by acidification produces compound X as the major product. X on treatment with CH3CO2O in the presence of catalytic amount of H2SO4 produces:

Choose an option

Show full solutionCorrect option: B
Correct answer
B

Step-by-step explanation

Two different reactions are taking place here Kolbe–Schmitt reaction and esterification reaction (treatment of the product of Kolbe–Schmitt reaction with (CH3CO)2O (ester). 

The two reactions can be written as follows:

1.Kolbe–Schmitt reaction: reaction of phenol with carbon dioxide in the presence of sodium hydroxide, followed by acidification converts phenol to 1−1− hydroxybenzoic acid (Salicylic acid).

 

2.Esterification reaction: The salicylic acid is then reacted with acetic anhydride (CH3CO)2O) to form aspirin.

 

solution

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Alcohols Phenols and Ethers chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2018, covering the Alcohols Phenols and Ethers chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.