JEE Main 2026 — Chemical Bonding and Molecular Structure Question with Solution
JEE Main 2026 (23 January Shift 1)
Question
Identify the molecule with maximum number of lone pairs of electrons (obtained using Lewis dot structure) among and . Choose the correct bond angle made by the central atom of the molecule .
Choose an option
Show full solutionCorrect option: B
Correct answer
B
Step-by-step explanation
Analyzing lone pairs on central atoms:
HNO₃: N is central with 3 bonds and 0 lone pairs
H₂SO₄: S is central with 4 bonds and 0 lone pairs
NF₃: N is central with 3 bonds and 1 lone pair
O₃: Central O with 2 bonding regions and 1 lone pair
NF₃ has maximum lone pairs (1) with the clearest structure. N undergoes sp³ hybridization with 1 lone pair and 3 bonding pairs giving trigonal pyramidal geometry. The F-N-F bond angle is reduced from ideal tetrahedral 109.5° due to lone pair repulsion, resulting in approximately 102°.
HNO₃: N is central with 3 bonds and 0 lone pairs
H₂SO₄: S is central with 4 bonds and 0 lone pairs
NF₃: N is central with 3 bonds and 1 lone pair
O₃: Central O with 2 bonding regions and 1 lone pair
NF₃ has maximum lone pairs (1) with the clearest structure. N undergoes sp³ hybridization with 1 lone pair and 3 bonding pairs giving trigonal pyramidal geometry. The F-N-F bond angle is reduced from ideal tetrahedral 109.5° due to lone pair repulsion, resulting in approximately 102°.
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This is a previous-year question from JEE Main 2026, covering the Chemical Bonding and Molecular Structure chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.