JEE Main 2026 — Chemical Bonding and Molecular Structure Question with Solution
JEE Main 2026 (02 April Shift 2)
Question
is isostructural with:
A.
B.
C.
D.
E.
Choose the correct answer from the options given below:
A.
B.
C.
D.
E.
Choose the correct answer from the options given below:
Choose an option
Show full solutionCorrect option: B
Correct answer
BC and E Only
Step-by-step explanation
In , the central sulphur atom has valence electrons. It forms sigma bonds with fluorine atoms and has lone pair. The steric number is , corresponding to hybridization, and the shape is see-saw.
In , the central bromine atom has valence electrons (). It forms sigma bonds and has lone pairs. The steric number is , corresponding to hybridization, and the shape is square planar.
In , the central carbon atom has valence electrons. It forms sigma bonds and has lone pairs. The steric number is , corresponding to hybridization, and the shape is tetrahedral.
In , the central iodine atom has valence electrons (). It forms sigma bonds and has lone pair. The steric number is , corresponding to hybridization, and the shape is see-saw.
In , the central xenon atom has valence electrons. It forms sigma bonds and has lone pairs. The steric number is , corresponding to hybridization, and the shape is square planar.
In , the central xenon atom has valence electrons. It forms sigma bonds ( with oxygen, with fluorine), pi bonds, and has lone pair. The steric number is , corresponding to hybridization, and the shape is see-saw.
Therefore, and are isostructural with .
Answer: C and E Only
In , the central bromine atom has valence electrons (). It forms sigma bonds and has lone pairs. The steric number is , corresponding to hybridization, and the shape is square planar.
In , the central carbon atom has valence electrons. It forms sigma bonds and has lone pairs. The steric number is , corresponding to hybridization, and the shape is tetrahedral.
In , the central iodine atom has valence electrons (). It forms sigma bonds and has lone pair. The steric number is , corresponding to hybridization, and the shape is see-saw.
In , the central xenon atom has valence electrons. It forms sigma bonds and has lone pairs. The steric number is , corresponding to hybridization, and the shape is square planar.
In , the central xenon atom has valence electrons. It forms sigma bonds ( with oxygen, with fluorine), pi bonds, and has lone pair. The steric number is , corresponding to hybridization, and the shape is see-saw.
Therefore, and are isostructural with .
Answer: C and E Only
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This is a previous-year question from JEE Main 2026, covering the Chemical Bonding and Molecular Structure chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.