JEE Main 2020 — Chemistry In Everyday Life Question with Solution
From: JEE Main 2020 (Online) 7th January Evening Slot
Question
The number of sp2 hybridised carbons present in "Aspartame" is
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Show full solutionCorrect answer: 9
Correct answer
9
Step-by-step explanation
Strcuture of Aspartame is:
Number of sp2 hybridised carbon atom is = 9
Number of sp2 hybridised carbon atom is = 9
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This is a previous-year question from JEE Main 2020, covering the Chemistry In Everyday Life chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.