JEE Main 2019ChemistryClassification of Elements and Periodicity in PropertiesMediumMCQ

JEE Main 2019 — Classification of Elements and Periodicity in Properties Question with Solution

JEE Main 2019 (12 Jan Shift 1)

Question

The element with Z=120 (not yet discovered) will be a/an

Choose an option

Show full solutionCorrect option: B
Correct answer
Balkaline earth metal.

Step-by-step explanation

Og1188s2 is the configuration for Z=120.

Since the differentiating electron is entering in the s-orbital, the element will belong to the s-block and the outermost s-orbital is having two electrons. Hence, It will belong to the alkaline earth metal group.

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Classification of Elements and Periodicity in Properties chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2019, covering the Classification of Elements and Periodicity in Properties chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.