JEE Main 2022PhysicsOscillationsMediumMCQ

JEE Main 2022 — Oscillations Question with Solution

JEE Main 2022 (26 Jun Shift 1)

Question

Time period of a simple pendulum in a stationary lift is T. If the lift accelerates with g6 vertically upwards then the time period will be
(Where g= acceleration due to gravity)

Choose an option

Show full solutionCorrect option: C
Correct answer
C67T

Step-by-step explanation

The time period of a simple pendulum is given by T=2πlg

In an upward accelerating frame the effective geff=g+a

⇒T2=2πlg+a=2πlg+g6

TT2=g+g6g=76

⇒T2=67T

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About this question

This is a previous-year question from JEE Main 2022, covering the Oscillations chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.