JEE Main 2023PhysicsOscillationsEasyNumerical

JEE Main 2023Oscillations Question with Solution

JEE Main 2023 (01 Feb Shift 1)

Question

The amplitude of a particle executing SHM is 3 cm. The displacement at which its kinetic energy will be 25% more than the potential energy is: ______ cm.

Enter your answer

Show full solutionCorrect answer: 2
Correct answer
2

Step-by-step explanation

Let x be the displacement at which its kinetic energy will be 25% more than the potential energy.

Given here, A=3 cm and KE=PE+PE4

So, KE=54PE

12mω2A2-x2=54×12mω2x2

A2-x2=54x2

9x24=A2

x=23A

 x=23×3 cm

x=2 cm

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Oscillations chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2023, covering the Oscillations chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.