JEE Main 2021PhysicsOscillationsEasyMCQ

JEE Main 2021 — Oscillations Question with Solution

JEE Main 2021 (27 Jul Shift 1)

Question

A particle starts executing simple harmonic motion (SHM) of amplitude a and total energy E. At any instant, its kinetic energy is 3E4, then its displacement y is given by:

Choose an option

Show full solutionCorrect option: D
Correct answer
Dy=a2

Step-by-step explanation

E=12Ka2
3E4=12 Ka2-y2v
34×12Ka2=12 Ka2-y2
y2=a2-3a24
y=a2

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About this question

This is a previous-year question from JEE Main 2021, covering the Oscillations chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.