JEE Main 2019PhysicsOscillationsEasyMCQ

JEE Main 2019 — Oscillations Question with Solution

JEE Main 2019 (10 Jan Shift 2)

Question

A hoop and a solid cylinder of same mass and radius are made of a permanent magnetic material with their respective axes. But the magnetic moment of hoop is twice of solid cylinder. They are placed in a uniform magnetic field in such a manner that their magnetic moments make a small angle with the field. If the oscillation periods of hoop and cylinder are Th and Tc respectively, then:

Choose an option

Show full solutionCorrect option: B
Correct answer
BTh=Tc

Step-by-step explanation

Time period of any magnetic body place in an external magnetic field is:-

T=2πIMB

Thoop=2πmR2MB ...... (1) Ihoop=mR2

Tc=2πmR22M2B  ...... (2) ISolid cylinder=mR22

From (1) and (2)

Th=Tc

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Oscillations chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2019, covering the Oscillations chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.