JEE Main 2023PhysicsOscillationsMediumMCQ

JEE Main 2023 — Oscillations Question with Solution

JEE Main 2023 (10 Apr Shift 2)

Question

For a periodic motion represented by the equation y=sinωt+cosωt the amplitude of the motion is

Choose an option

Show full solutionCorrect option: D
Correct answer
D2

Step-by-step explanation

Given the equation of motion is

y=sinωt+cosωt   ...1

Simplify equation (1) to obtain the standard form:

y=2sinωtcosπ4+cosωtsinπ4=2sinωt+π4   ...2

Comparing equation (2) with standard equation of SHM y=Asinωt+ϕ, we get amplitude of the given oscillation as 2.

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Oscillations chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2023, covering the Oscillations chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.