JEE Main 2024PhysicsOscillationsEasyNumerical

JEE Main 2024Oscillations Question with Solution

JEE Main 2024 (06 Apr Shift 1)

Question

A particle is doing simple harmonic motion of amplitude and time period . The maximum velocity of the particle is _______ .

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Show full solutionCorrect answer: 12
Correct answer
12

Step-by-step explanation

We know $\begin{aligned} \mathrm{V}_{\max } & =\omega \mathrm{A} \quad \text { at mean position } \\ & =\frac{2 \pi}{\mathrm{T}} \mathrm{A}=\frac{2 \pi}{\pi} \times 0.06=0.12 \mathrm{~m} / \mathrm{sec} \\ \mathrm{V}_{\max } & =12 \mathrm{~cm} / \mathrm{sec} \end{aligned}$

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About this question

This is a previous-year question from JEE Main 2024, covering the Oscillations chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.