JEE Main 2022PhysicsOscillationsMediumNumerical

JEE Main 2022 — Oscillations Question with Solution

JEE Main 2022 (26 Jul Shift 2)

Question

As per given figures, two springs of spring constants K and 2 K are connected to mass m. If the period of oscillation in figure (a) is 3 s, then the period of oscillation in figure (b) will be x s. The value of x is _____ .

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Show full solutionCorrect answer: 2
Correct answer
2

Step-by-step explanation

In figure (a), the springs are connected in series. Therefore,

Keq=K1K2K1+K2=K×2KK+2K=2K3

Therefore, the time period

Ta=2πmKeq=2πm2K3=2π3m2K

In figure (b), the springs are connected in parallel. Therefore,

Keq=K1+K2=3K

Therefore, the time period

Tb=2πmKeq=2πm3K

Now,

TaTb=92⇒Tb=23Ta=2 s

Hence, x=2

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About this question

This is a previous-year question from JEE Main 2022, covering the Oscillations chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.