JEE Main 2022PhysicsOscillationsEasyMCQ

JEE Main 2022 — Oscillations Question with Solution

JEE Main 2022 (24 Jun Shift 2)

Question

Two massless springs with spring constants 2k and 9k, carry 50 g and 100 g masses at their free ends. These two masses oscillate vertically such that their maximum velocities are equal. Then, the ratio of their respective amplitudes will be :

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Show full solutionCorrect option: A
Correct answer
A3:2

Step-by-step explanation

Maximum velocity is given by vmax=ωA =kmA

Here, k1m1A1=k2m2A2

  ⇒2k50×10-3A1=9k100×10-3A2

  ⇒2A1=3A2

Thus, ratio of amplitude is A1A2=32=3:2.

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About this question

This is a previous-year question from JEE Main 2022, covering the Oscillations chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.