JEE Main 2015PhysicsOscillationsEasyMCQ

JEE Main 2015Oscillations Question with Solution

JEE Main 2015 (04 Apr)

Question

For a simple pendulum, a graph is plotted between its kinetic energy (K.E.) and potential energy (P.E.) against its displacement d. which one of the following represents these correctly? (graphs are schematic and not drawn to scale)

Choose an option

Show full solutionCorrect option: C
Correct answer
C

Step-by-step explanation

For simple pendulum performing the simple harmonic motion, displacement, y=Asinωtv=dydt=ωAcosωt=ωA2-y2⇒K.E.=12mv2
This represents a downward parabola, Y=±AK.E.=12ω2m A2-A2=0P.E.=122y2. This represents an upward parabola. On plotting graphs of potential energy & kinetic energy.

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About this question

This is a previous-year question from JEE Main 2015, covering the Oscillations chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.