JEE Main 2016PhysicsOscillationsEasyMCQ

JEE Main 2016Oscillations Question with Solution

JEE Main 2016 (09 Apr Online)

Question

Two particles are performing simple harmonic motion in a straight line about the same equilibrium point. The amplitude and time period for both particles are same and equal to A and T, respectively. At time t=0 one particle has displacement A while the other one has displacement -A2 and they are moving towards each other. If they cross each other at time t, then t is:

Choose an option

Show full solutionCorrect option: D
Correct answer
DT6

Step-by-step explanation



Angle covered to meet =60o=π3rad

Therefore,  t= θ ω = π 3 × T 2π = T 6

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About this question

This is a previous-year question from JEE Main 2016, covering the Oscillations chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.