JEE Main 2014PhysicsOscillationsMediumMCQ

JEE Main 2014Oscillations Question with Solution

JEE Main 2014 (09 Apr Online)

Question

A particle which is simultaneously subjected to two perpendicular simple harmonic motions represented by;  x=a1cosωt   and y=a2cos2ωt traces a curve given by :

Choose an option

Show full solutionCorrect option: D
Correct answer
D

Step-by-step explanation

x=a1cosωt

y=a2cos2ωt

=a22cos2ωt-1

=a22 xa12-1

ya2=2x2a12-1

a12y=2a2x2-a12a2

which is a parabola symmetrical about y-axis opening in upward direction

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About this question

This is a previous-year question from JEE Main 2014, covering the Oscillations chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.