JEE Main 2017PhysicsOscillationsMediumMCQ

JEE Main 2017 — Oscillations Question with Solution

JEE Main 2017 (09 Apr Online)

Question

A block of mass 0.1 kg is connected to an elastic spring of spring constant 640 N m-1 and oscillates in a damping medium of damping constant 10-2 kg s-1 . The system dissipates its energy gradually. The time taken for its mechanical energy of vibration to drop to half of its initial value, is closest to-

Choose an option

Show full solutionCorrect option: D
Correct answer
D7 s

Step-by-step explanation

Given,

 E=Eo2 
⇒A=Ao2
Amplitude of damped oscillation=A=Aoe-bt2m

⇒Ao2=Aoe-bt2m 

2=ebt2m 

ln⁡2=bt2m=10-22×0.1t=0.1t2

t2=10ln⁡2=10×12×0.693

t=10×0.693=6.93

t≈7 s.  

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About this question

This is a previous-year question from JEE Main 2017, covering the Oscillations chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.