JEE Main 2026 — Biomolecules Question with Solution
JEE Main 2026 (22 January Shift 2)
Question
Match List - I with List - II.
Choose the correct answer from the options given below :
Choose the correct answer from the options given below :
Choose an option
Show full solutionCorrect option: D
Correct answer
DA-IV, B-I, C-II, D-III
Step-by-step explanation
Glucose reactions: A + Hydroxylamine forms glucoxime (IV) via condensation with aldehyde group.
B + Br₂ water oxidizes aldehyde to carboxylic acid, forming gluconic acid (I).
C + Excess acetic anhydride acetylates all hydroxyl groups to form glucose pentaacetate (II).
D + Concentrated HNO₃ oxidizes both aldehyde and primary alcohol groups to form saccharic acid (III).
The correct matching is A-IV, B-I, C-II, D-III.
B + Br₂ water oxidizes aldehyde to carboxylic acid, forming gluconic acid (I).
C + Excess acetic anhydride acetylates all hydroxyl groups to form glucose pentaacetate (II).
D + Concentrated HNO₃ oxidizes both aldehyde and primary alcohol groups to form saccharic acid (III).
The correct matching is A-IV, B-I, C-II, D-III.
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This is a previous-year question from JEE Main 2026, covering the Biomolecules chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.