JEE Main 2021ChemistryChemical Bonding and Molecular StructureEasyMCQ

JEE Main 2021 — Chemical Bonding and Molecular Structure Question with Solution

JEE Main 2021 (26 Feb Shift 2)

Question

Match List-I with List-II.

List-I List-II
(Molecule) (Bond order)
(a) Ne2 (i) 1
(b) N2 (ii) 2
(c) F2 (iii) 0
(d) O2 (iv) 3

Choose the correct answer from the options given below:

Choose an option

Show full solutionCorrect option: B
Correct answer
Ba→iii, b→iv, c→i, d→ii

Step-by-step explanation

Bond order = 12​ (number of electrons in bonding MO -number of electrons in anti-bonding MO)

(a) Ne2= Total eΘ=20

B.O. =10-102=0

(b) N2= Total e⊝=14

B.O. =10-42=3

(c) F2= Total e⊝=18

B.O. =10-82=1

(d) O2= Total e⊝=16

B.O. =10-62=2

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About this question

This is a previous-year question from JEE Main 2021, covering the Chemical Bonding and Molecular Structure chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.