JEE Main 2021ChemistryChemical Bonding and Molecular StructureMediumNumerical

JEE Main 2021 — Chemical Bonding and Molecular Structure Question with Solution

JEE Main 2021 (01 Sep Shift 2)

Question

The spin-only magnetic moment value of B2+ species is ×10-2BM (Nearest integer)

[ Given : 3=1.73]

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Show full solutionCorrect answer: 173
Correct answer
173

Step-by-step explanation

 In B2number of electron +=9

B2=+(σ1 s)2σ*1 s2(σ2 s)2σ⋆2 s2π2px=1π2py0,

so unpaired electron =1

μ=n(n+2)B

μ=3   B.M. =1.73=173×10-2 B.M 

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About this question

This is a previous-year question from JEE Main 2021, covering the Chemical Bonding and Molecular Structure chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.