JEE Main 2019ChemistryChemical Bonding and Molecular StructureMediumMCQ

JEE Main 2019Chemical Bonding and Molecular Structure Question with Solution

JEE Main 2019 (10 Jan Shift 1)

Question

The type of hybridization and no. of lone pair(s) of electron of Xe in XeOF4 , respectively, are:

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Show full solutionCorrect option: A
Correct answer
Asp3d2 and 1

Step-by-step explanation



Steric no. =6, hybridisation =sp3d2

No. of lone pairs on Xe=1

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About this question

This is a previous-year question from JEE Main 2019, covering the Chemical Bonding and Molecular Structure chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.